1. divide by the GCF it will give you smaller numbers
2.then factor
3. set each factor to = 0
4. you will have 2 values for x
hope this helps
The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.
<h3>What is the significance of "Area under the curve"?</h3>
This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.
<h3>What is the justification for the above answer?</h3>
Area = 
= 
= e¹-(1/2-0); or
Area = e -1.5 Squared Unit
The related Graph is attached accordingly.
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Answer:
28 cubs
Step-by-step explanation:
Since one and a half bear produces one and a half cub, then 6 bears will produce 6 cubs in one and a half days.
We need to find 7 days, though but we have the rate for six bears for 1.5 days which 6 bears one a half day.
What is the rate for a day?
6/1.5 =
6 bears produce 4 cubs a day.
Now just do 4 x 7
4 x 7 = 28
Therefore, 6 bears produce 28 cubs in 7 days.
Answer:
x = 2/3 or x = -1
Step-by-step explanation by completing the square:
Solve for x:
3 x^2 + x - 2 = 0
Divide both sides by 3:
x^2 + x/3 - 2/3 = 0
Add 2/3 to both sides:
x^2 + x/3 = 2/3
Add 1/36 to both sides:
x^2 + x/3 + 1/36 = 25/36
Write the left hand side as a square:
(x + 1/6)^2 = 25/36
Take the square root of both sides:
x + 1/6 = 5/6 or x + 1/6 = -5/6
Subtract 1/6 from both sides:
x = 2/3 or x + 1/6 = -5/6
Subtract 1/6 from both sides:
Answer: x = 2/3 or x = -1
Answer:
h(x - 1) = -5x - 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Terms/Coefficients
Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
h(x) = -5x - 7
<u>Step 2: Find</u>
- Substitute in <em>x </em>[Function h(x)]: h(x - 1) = -5(x - 1) - 7
- [Distributive Property] Distribute -5: h(x - 1) = -5x + 5 - 7
- Combine like terms: h(x - 1) = -5x - 2