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2 years ago

What inequalities satisfy the region R in the diagram?

Mathematics

1 answer:

krek1111 [17]2 years ago

4 0

Answer:

y ≤ -x - 4

x > -1

y ≥ 4

Step-by-step explanation:

For the sloped line, we can see that the y-intercept is -4 and the x-intercept is -4.

This means at x = 0, y = - 4 and at y = 0, x = -4. We also see that the bottom of the line is shaded and that the line is not broken.

Thus, the inequality is; y ≤ -x - 4

For the vertical line, we can see it has only an x-intercept at x = - 1. We also see that the line is broken which means the equal to symbol is not part of the inequality. Also, the shaded part is to the right. Thus, the inequality is:

x > -1

For the horizontal line, we see that it has only a y-intercept at y = 4. We also see that the line is not broken which means the equal to symbol is part of the inequality. Also, the shaded part is above. Thus, the inequality is:

y ≥ 4

Therefore, the inequalities that satisfy the region R are:

y ≤ -x - 4

x > -1

y ≥ 4

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Jackie runs and dances for a total of 55 minutes every day. She dances for 25 minutes longer than she runs.

AlladinOne [14]

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Answer:

A: x + y = 55; y - x = 25

B: 15 minutes running

C: no

Step-by-step explanation:

The two equations relate to the total number of minutes, and to the difference specified in the problem statement.

x + y = 55 . . . . . . total time is 55 minutes

y = x + 25 . . . . . . dances 25 minutes longer

We can substitute for y in the first equation to find the value of x, the time spent running.

x + (x +25) = 55

2x = 30 . . . . subtract 25

x = 15 . . . . . . divide by 2

Jackie spends 15 minutes running each day.

The value of y from is found using the second equation:

y = x +25 = 15 +25 = 40

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A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

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