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Marrrta [24]
3 years ago
5

What inequalities satisfy the region R in the diagram?

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

y ≤ -x - 4

x > -1

y ≥ 4

Step-by-step explanation:

For the sloped line, we can see that the y-intercept is -4 and the x-intercept is -4.

This means at x = 0, y = - 4 and at y = 0, x = -4. We also see that the bottom of the line is shaded and that the line is not broken.

Thus, the inequality is; y ≤ -x - 4

For the vertical line, we can see it has only an x-intercept at x = - 1. We also see that the line is broken which means the equal to symbol is not part of the inequality. Also, the shaded part is to the right. Thus, the inequality is:

x > -1

For the horizontal line, we see that it has only a y-intercept at y = 4. We also see that the line is not broken which means the equal to symbol is part of the inequality. Also, the shaded part is above. Thus, the inequality is:

y ≥ 4

Therefore, the inequalities that satisfy the region R are:

y ≤ -x - 4

x > -1

y ≥ 4

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Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.​

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

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You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

4 0
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1/4 +1/3 divided by4/5
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Now we are going to do the multiplication since multiply and division is before adding and subtraction.

1/3 times 5/4 = 5/12

Now we have to add 1/4+5/12

With adding ( and subtracting) we have to find the common denominator which is 12

So now we have 3/12 + 5/12 = 8/12 which reduces to 2/3

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