Let us assume that the small no. is x.
So the larger no. is 16+x
so x+16+x=68
2x+16=68
2x=68-16
2x=52
X= 52/2 = 26
The small number is 26
The larger no. = 16 + 26
The larger no. Is 42
Let's go through the answer choices one by one:
A. False. The line segment contains more than just the endpoints
B. False. There are points in this description that extend beyond the endpoints. If this was a line instead of a segment, then choice B would be the answer
C. True. This is the answer. Though your teacher should have added "collinear" to the sentence to make it clear that the points are between M and N, and also collinear to M and N. All of these points form the line segment MN
D. False. That would be the perpendicular bisector of MN
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So once again, the final answer is choice C
The surface area of the box is being referred to as A
The surface area will be the sum of the four rectangular sides' areas and the base area.
Base area = x²
Rectangular side area = xh
A = x² + 4xh
Volume is, as you said,
V = x²h
Lets substitute h from the formula of A to obtain A in our final answer. Substituting x is possible, but more difficult
(A - x²)/4x = h
V = (x²) * (A - x²)/4x
V = (Ax - x³)/4
Supplements add up to 180°
so just subtract 164 from 180
180
<u>-164
</u> 16
