She didn't estimate her answer first
WHAT IS THE QUESTION ON KENDRA'S HOMEWORK?
There are four aces, 12 face cards and 4 7s in a standard 52 card deck. The probability of getting an ace on the first draw is 4/52 or 1/13. For the second draw there are now 51 cards in the deck (assuming the draws are without replacement), so the probability of getting a face card is 12/51. Given an ace and a face card on the first two draws, the probability of a 7 on the third draw is 4/50 or 2/25. The probability of getting all three is 1/13*12/51*2/25.
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Related Questions (More Answers Below)
Answer:
i dont know but good luck! <3
Step-by-step explanation:
Answer:
a) 1/6
b) 1/36
c) 1/720
d) 1/3
Step-by-step explanation:
a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:
