Question

The probability that the space shuttle is launched on the designated day is 80%. Assume that

Answer 1

Answer:

0.9728

Explanation:

P(launch), p = 80% = 0.8

(1 - p) = 1 - 0.80 = 0.2

Number of launches = 4

We can apply the binomial probability formula :

P(x =x) = nCx * p^x * (1 - p)^(n - r)

Probability that More than 1 is launched

P(x > 1) = p(x = 2) + p(x = 3) + p(x = 4)

P(x = 2) :

4C2 * 0.8^2 * 0.2^2

6 * 0.64 * 0.04 = 0.1536

P(x = 3) :

4C3 * 0.8^3 * 0.2^1

4 * 0.512 * 0.2 = 0.4096

P(x = 4) :

4C4 * 0.8^4 * 0.2^0

1 * 0.4096 * 1 = 0.4096

P(x > 1) = 0.1536 + 0.4096 + 0.4096

P(x > 1) = 0.9728