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yarga [219]
3 years ago
12

If x = y then what is x don't answer that the among us code isTMZFUF

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

lol ill join. mark this brainliest i triple dog dare you

Step-by-step explanation:

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Find the circumference of a circle with a diameter of 7 cm.
professor190 [17]

Answer:

3.14

Step-by-step explanation:

if you want the exact answer you can multiply 7 by the value of

, that is = 3.14

3 0
4 years ago
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Need help 59 points if you answer this 6th gade questions
Pani-rosa [81]
I think the answer is 32.
4 0
4 years ago
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Cual de estos tipos de mentalidad puede contribuir a superar situaciones de no inclusión porque​
posledela

La mentalidad de crecimiento, ya que a diferencia de la mentalidad fija, nos permite ver en otras personas la mentalidad de mejorar y perseverar.

5 0
4 years ago
Jaylon Bedford ordered a combo meal that included 2 hamburgers and a drink. The combo cost $8.50. If the drink is $1.50, how muc
valentinak56 [21]

Answer:

$3.50 each

Step-by-step explanation:

First subtract the drink price from the total,$8.50-$1.50=$7. then divide that amount by 2 since he got 2 burgers. $7/2=$3.50.Each burger is $3.50.

7 0
3 years ago
Proof that :<br><img src="https://tex.z-dn.net/?f=%20%7Bsin%7D%5E%7B2%7D%20%5Ctheta%20%2B%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%5Cth
Arisa [49]

Answer:

Solution given:

Right angled triangle ABC is drawn where <C=\theta

we know that

\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}

\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC}

Now

left hand side

\displaystyle {sin}^{2} \theta + {cos}^{2} \:\theta

Substituting value

(\frac{AB}{AC})²+(\frac{BC}{AC})²

distributing power

\frac{AB²}{AC²}+\frac{BC²}{AC²}

Taking L.C.M

\displaystyle \frac{AB²+BC²}{AC²}....[I]

In ∆ABC By using Pythagoras law we get

\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

\displaystyle \frac{AC²}{AC²}

=1

Right hand side

<h3><u>proved</u></h3>

8 0
3 years ago
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