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2 years ago

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Evaluate the function g(x) = 8x + 16 when x = -3,0, and 8. g(-3) = ) 0 g(0) = 9(8) =

1 answer:

Ilia_Sergeevich [38]2 years ago

7 0

Answer:

Step-by-step explanation:

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Which fraction shows the ratio 16:200 as a fraction simplified form

Molodets [167]

Answer:

16:200

4:50

2:25

So answer is C) 2/25

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3 years ago

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Two rectangles are similar. The first rectangle has a length of 15 cm and a width of 10 cm. The width of the second rectangle is

Margarita [4]

Answer:

Its length is 37.5 cm.

Step-by-step explanation:

If two rectangles are similar, their sides are proportional, that is, they have equal ratios. So

The first rectangle has a length of 15 cm and a width of 10 cm. The width of the second rectangle is 25 cm.

So

$\frac{15}{10} = \frac{l}{25}$

$10l = 25*15$

Simplifying by 10.

$l = 2.5*15 = 37.5$

Its length is 37.5 cm.

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3 years ago

Just having lil problem with this math problem if anyone can help me please solving. thanks

Cloud [144]

1-2 is right
3 you have to draw a shape and then put 3 lines then shade in one
number 4 you have to draw a shape again but put 8 lines through then shade 1
5 your answer is 1/8
6 your answer is 1/4
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2 years ago

How many places do you need to move the decimal to the left to write the number below in scientific notation? 60000000000

garik1379 [7]

60,000,000,000 in scientific notation is 6 x 10^10 so you move the decimal 10 times.

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2 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

So

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

So

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

So

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago