1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
11Alexandr11 [23.1K]
3 years ago
13

PLZ HELP ME I WAS STUCK ON THIS FOR 30 MINS WILL GIVE BRAINLIST

Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

Step-by-step explanation:

6³ is not equal to 18, that is 6x3

6³= 6x6x6=216

so the correct volume is V= 904.7 cm³

SVETLANKA909090 [29]3 years ago
4 0

Answer:

Step-by-step explanation:

6^3 is the error, 6^3 is 216.

the correct volume is   904.32

You might be interested in
22. At Thanksgiving dinner Deborah ate a portion of turkey (673 calories); mashed potatoes (408 calories); stuffing (519 calorie
ahrayia [7]
Approximately 2600 calories if rounded, or exactly 2620 calories, I believe..
7 0
3 years ago
Read 2 more answers
A random sample of 37 second graders who participated in sports had manual dexterity scores with mean 32.19 and standard deviati
Hunter-Best [27]

Answer:

We conclude that the second graders who participate in sports does not have a higher mean dexterity score.

Step-by-step explanation:

We are given that a random sample of 37 second graders who participated in sports had manual dexterity scores with mean 32.19 and standard deviation 4.34. An independent sample of 37 second graders who did not participate in sports had manual dexterity scores with mean 31.68 and standard deviation 4.56.

We have to conduct a hypothesis test to see whether sufficient evidence exists to indicate that second graders who participate in sports have a higher mean dexterity score.

<em>Let </em>\mu_1<em> = population mean dexterity scores for second graders who participated in sports</em>

<em>       </em>\mu_2<em> = population mean dexterity scores for second graders who did not participated in sports</em>

SO, Null Hypothesis, H_0 : \mu_1 \leq \mu_2  or  \mu_1-\mu_2\leq0  {means that the second graders who participate in sports have less than or equal mean dexterity score}

Alternate Hypothesis, H_a : \mu_1> \mu_2  or  \mu_1-\mu_2 > 0  {means that the second graders who participate in sports have a higher mean dexterity score}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                T.S. = \frac{(\bar X_1 - \bar X_2)-(\mu_1-\mu_2)}{s_p \sqrt{\frac{1 }{n_1} +\frac{1 }{n_2}} }  ~ t__n__1+n_2-_2

where, \bar X_1 = sample mean dexterity scores for 37 second graders who participated in sports = 32.19

\bar X_2 = sample mean dexterity scores for 37 second graders who did not participated in sports = 31.68

 s_1 = standard deviation for 37 second graders who participated in sports = 4.34

 s_2 = standard deviation for 37 second graders who did not participated in sports = 4.56

 n_1  = sample size for second graders who participated in sports = 37

 n_2  = sample size for second graders who did not participated in sports = 37

Here, s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } = s_p = \sqrt{\frac{(37-1)\times 4.34^{2}+(37-1)\times 4.56^{2}  }{37+37-2} } = 4.45

So, <u>test statistics</u> =  \frac{(32.19-31.68)-(0)}{4.45 \times \sqrt{\frac{1 }{37} +\frac{1 }{37}} }  ~ t_7_2

                             = 0.493

<em> So, at 0.05 level of significance, the t table gives critical value of 1.6684 at 72 degree of freedom for one-tailed test. Since our test statistics is less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the second graders who participate in sports does not have a higher mean dexterity score.

6 0
3 years ago
What is 2 wholes and 5/6 as a mixed number​
kakasveta [241]
17/6 should be the correct answer
6 0
3 years ago
Read 2 more answers
Please read the following picture below and use 3.142 instead of <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title
Marina86 [1]

Check the picture below.

now, let's notice the larger "yellow" semicircle, it has a gap, the gap on the right is of a semicircle with a diameter of 10, BUT it also has a descender on the left, a part that's hanging out, that part is also a semicircle.

so if we use the descending semicircle to fill up the gap on the right, we'll end up with a filled up larger semicircle, whose diameter is 20, and whose radius is 10 cm.

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=10 \end{cases}\implies A=\pi 10^2\implies A=100\pi \\\\\\ \stackrel{\textit{half of that for a semicircle}}{A=\cfrac{100\pi }{2}}\implies A=50\pi \implies \stackrel{\pi =3.142}{A=157.1}

8 0
3 years ago
 what 2 numbers should be placed in the blanks below so that the difference between consecutive numbers is the same?      17,_,_
Komok [63]
The answer is 25, 33. The difference between each consecutive number is 8.
5 0
3 years ago
Other questions:
  • At a certain college, the probability that a student attends full-time is 0.320 and the probability that the student attends par
    10·1 answer
  • Jessica was comparing the rainfall, in inches, for three cities during the month of March. · Atlanta (A) had a decrease of 0.25
    9·1 answer
  • Which expressions are equivalent to 3x+3(x+y).
    13·1 answer
  • Question 22. Given that ... what is the expression for C?
    15·2 answers
  • Find mCD<br> Help please :/
    14·1 answer
  • The equation for the ellipse given is 4x^2+9y^2-16x+18y-11​
    6·1 answer
  • Can ya solve this?? <br> Big grade pls
    8·1 answer
  • Can someone explain this / answer, Its a picture
    6·1 answer
  • Ok so Like this is for the LGBTQ+ females......AND ONLY THEM PLZ
    5·2 answers
  • The volume of the sphere is 500 - cubic units.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!