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Inga [223]
3 years ago
8

How do i do this ????

Mathematics
1 answer:
Temka [501]3 years ago
4 0

the wind is going to change to the process of getting a pudding and the tens 1 minus the process of people who were not in the

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1.
anygoal [31]
Where is the picture for the problem?
7 0
3 years ago
Find K if K divided by 64 equals 4
pshichka [43]

Solve:

\frac{k}{64}=4

We need to isolate k, so multiply both sides by the denominator, which is 64. When we do that, the fraction will cancel and we get:

k=256

If you want to check, plug in your answer to the original equation and see if it is true:

\frac{256}{64}=4

4=4

This statement is true, so k=256.

4 0
4 years ago
Read 2 more answers
Adam uses coconut milk for the dessert.
elena-14-01-66 [18.8K]
Do you mean 3.14 for pi or just 3?

5 0
4 years ago
A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n
mafiozo [28]

Answer:

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

\hat p=\frac{40}{120}=0.333 estimated proportion of strawberries damaged

p_o=0.25 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0
3 years ago
0.09 is 10 times as much as ?
ANEK [815]
To find out the answer we divide 0.09 by 10: 0.09÷10=0.009. Therefore, 0.09 is 10 times as much as 0.009.
5 0
3 years ago
Read 2 more answers
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