Help!!!

Answer plz, i will give brainliest XD 100 points ppl, lol

castortr0y [4]

Answer:

A) x=9, x=-2, x=2

Step-by-step explanation:

(x-9)(x+2)(x-2)=0

x-9=0

x+2=0

x-2=0

x=9, x=-2, x=2

8 0

3 years ago

Read 2 more answers

HELP I NEED HELP ASAP

miss Akunina [59]

Answer:

The answer is C.

$(3x + 2)(x - 4) = 0 \\ 3x + 2 = 0 \: \: \: \: and \: \: x - 4 = 0 \\ x = \frac{ - 2}{3} \: \: \: and \: \: \: \: x = 4$

6 0

3 years ago

The graph below shows the relationship between pounds of dog food and total cost, in dollars, for the dog food. A coordinate gra

n200080 [17]

We know that x-axis represents weight of dog food in pounds

AND y-axis represents Total cost in dollars

AND a line connects (0,0) and (10,5)

Based on the information we can plot a graph that can be seen in the attached image. The line represents y = $\frac{x}{2}$

Now, let's look at each of the statements to see which is true and which is false:

A) Point (0, 0) shows the cost is $0 for 0 pound of dog food.

(0,0) indicates that the cost for 0 pound dog food is $0. Hence, this statement is true.

B) Point (1, 0.5) shows the cost is $1.00 for 0.5 pound of dog food.

(1,0.5) indicates that the cost for 1 pound dog food is $0.5. Hence, this statement is false.

C) Point (2, 1) shows that 2 pounds of dog food cost $1.

(2,1) indicates that the cost for 2 pounds dog food is $1. Hence, this statement is true.

D) Point (4, 2) shows the cost is $4 for 2 pounds of dog food.

(4,2) indicates that the cost for 4 pounds dog food is $2. Hence, this is false.

E) Point (10, 5) shows that 10 pounds of dog food costs $5

(10,5) indicates the cost for 10 pounds dog food is $5. Hence, this is true.

8 0

3 years ago

Read 2 more answers

Find the inverse of the function. f(x) = the cube root of quantity x divided by seven. - 9

elena-14-01-66 [18.8K]

To solve

replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

so
I'm not sure if it is
$f(x)=\sqrt[3]{\frac{x}{7}}-9$ or
$f(x)=\sqrt[3]{\frac{x}{7}-9}$

first one
$f(x)=\sqrt[3]{\frac{x}{7}}-9$
replace f(x) with y
$y=\sqrt[3]{\frac{x}{7}}-9$
switch x and y
$x=\sqrt[3]{\frac{y}{7}}-9$
solve for y
$x+9=\sqrt[3]{\frac{y}{7}}$
$(x+9)^3=\frac{y}{7}$
$7(x+9)^3=y$
replace y with f⁻¹(x)
$f^{-1}(x)=7(x+9)^3$

2nd one
$f(x)=\sqrt[3]{\frac{x}{7}-9}$
replce f(x) with y
$y=\sqrt[3]{\frac{x}{7}-9}$
switch x and y
$x=\sqrt[3]{\frac{y}{7}-9}$
solve for y
$x^3=\frac{y}{7}-9$
$x^3+9=\frac{y}{7}$
$7(x^3+9)=y$
replace y with f⁻¹(x)
$f^{-1}(x)=7(x^3+9)$

if you meant $f(x)=\sqrt[3]{\frac{x}{7}}-9$ then the inverse is $f^{-1}(x)=7(x+9)^3$

if you meant $f(x)=\sqrt[3]{\frac{x}{7}-9}$ then the inverse is $f^{-1}(x)=7(x^3+9)$

7 0

3 years ago

Need help asap …………………………………..

nirvana33 [79]

Answer:

7 $\frac{5}{6}$