1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3
check: abs(3/2-1/3)-1=1/6, abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6
3 is a root
2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3
check : abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6, abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6, 7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3 is also root
so two roots 3 and -5/3(that can be written as -1 2/3)
<h3>
Answer:</h3>
y = 2x + 5
<h3>
Step-by-step explanation:</h3>
<u>Definitions</u>:
Slope Intercept form; y = mx + b
m = slope
b = y intercept
Step 1: Since the slope is given plug it into y = mx
y = 2x + b
Step 2: Plug a points' x and y into their corresponding spots to solve for b
(33) = 2(14) + b
Simplify and solve
33 = 28 + b
-28 -28
5 = b
Plug both your slope in and your y intercept into y = mx + b
y = 2x + 5
So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Given =
Two similar pyramid have base area of 12.2 cm² and 16 cm².
surface area of the larger pyramid = 56 cm²
find out the surface area of the smaller pyramid
To proof =
Let us assume that the surface area of the smaller pyramid be x.
as surface area of the larger pyramid is 56 cm²
Two similar pyramid have base area of 12.2 cm² and 16 cm².
by using ratio and proportion
we have
ratio of the base area of the pyramids : ratio of the surface area of the pyramids
x = 12.2 ×56×
by solvingthe above terms
we get
x =42.7cm²
Hence the surface area of the smaller pyramid be 42.7cm²
Hence proved
Answer:
Step-by-step explanation:
The formula for determining the circumference of a circle is expressed as
Circumference = 2πr
Where
r represents the radius of the circle
π is a constant whose value is 3.14
From the information given,
Radius = 6 cm
Therefore,
Circumference = 2 × 3.14 × 6
Circumference = 37.68 cm
The formula for determining the area of a circle is expressed as
Area = πr²
Area = 3.14 × 6² = 113.04 cm²
