The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
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X2 + 12 = 7x x2 – 7x + 12 = 0factor the equation (x – 3 ) ( x – 4 ) = 0 Then equating both factor to 0 X – 3 = 0 X = 3 And X – 4 = 0 X = 4 So the answer is X = 3 X =4
Answer:
its not showing up
Step-by-step explanation:
Answer:
(-8, -6)
Step-by-step explanation:
Given the Point G is (-8,6) if Point J is a reflection of point G and is reflected across the x axis, to get the coordinate of point J, we will negate the y coordinate while retaining the x coordinate value
J = (-8, -(6))
J = (-8, -6)
Hence the required coordinate of J is (-8, -6)
equivalent
1) 3^6
4) 3^-4 · 3^10
8) (3 · 3) · (3 · 3 · 3 · 3)
Step-by-step explanation:
![= {3}^{2} \times {3}^{4}](https://tex.z-dn.net/?f=%20%3D%20%20%7B3%7D%5E%7B2%7D%20%20%5Ctimes%20%20%7B3%7D%5E%7B4%7D%20)
![= {3}^{(2 + 4)}](https://tex.z-dn.net/?f=%20%3D%20%20%7B3%7D%5E%7B%282%20%2B%204%29%7D%20)
![= {3}^{6}](https://tex.z-dn.net/?f=%20%3D%20%20%7B3%7D%5E%7B6%7D%20)
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equivalent
1) 3^6
4) 3^-4 · 3^10
8) (3 · 3) · (3 · 3 · 3 · 3)