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Thepotemich [5.8K]
3 years ago
15

Find the area of the semicircle

Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

3.92yd

Step-by-step explanation:

pi r²÷2

pi 2.5²÷2=3.92

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What is the radius of the circle given by the equation below? x2 - 2x + y2 - 2y - 98 = 0?
valina [46]
Complete the square for the given equation
x² - 2x + ____ + y² - 2y + _____ = 98
x² - 2x + (1) + y² - 2y + (1) = 98 + (1) + (1)
(x - 1)² + (x - 1)² = 100
(x - 1)² + (x - 1)² = 10²

Now the equation is in the form (x - h)² + (y - k)² = r²

Radius = 10



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3 years ago
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A regular bar is 5 ounces and costs $1.25 A gigantic bar is 2 pounds and costs $6.98.
kolbaska11 [484]

Answer:

An experiment is done to see the health effect of large amounts of aspirin on rats. ... 2. Apples sell for 43 cents a pound. How much do 3.2 pounds of apples cost? ... A solid gold nugget is 23.5 ounces. How much is it worth? 23.5 oz x. $500 lez ... 5. A chocolate bar weighs 4.00 ounces.

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3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
4 years ago
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