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Ket [755]
3 years ago
13

Need help ASAP! Thanks

Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

A = 1, B = 1

Step-by-step explanation:

From the question

(2x+1)/(x²+x) = A/x + B/(x+1)

(2x+1)/(x²+x) = [A(x+1)+(Bx)]/(x²+x)

Equation the numerator

2x+1 ≡ A(x+1) +Bx

2x+1 ≡ Ax+A+Bx

From the above,

A = 1.

And,

2x = Ax+Bx................ Equation 1

A+B = 2

Substitute the value of A into Equation 1

1+B = 2

B = 2-1

B = 1

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Determine the domain of the function h=9x/x(x^2-49)
Juliette [100K]

ANSWER

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

EXPLANATION

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This function is defined for values where the denominator is not equal to zero.

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Or

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

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