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Alex73 [517]
3 years ago
13

Which expression can be used to find the value of x in the triangle shown?

Mathematics
1 answer:
Marina86 [1]3 years ago
6 0
The correct answer is A because you have to cross multiply x/20! Hope this helps!
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What is m-a = n+p, for a
sergeinik [125]

Answer:

A=m-n-p

Step-by-step explanation:

So solve for a, we have to isolate it on one side, so -a=n+p-m. So a=m-n-p

5 0
3 years ago
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Please answer within the next 7 min, giving 38 points of a ligament answer!
frosja888 [35]
The answer is choice C
6 0
3 years ago
Kunicki uses a medium and a large measuring cup to measure the ingredients to make his famous Buttery Oatmeal Raisin Cookies. He
Nonamiya [84]

Answer:

L = 16oz

M = 12oz

S = 8oz

Step-by-step explanation:

8 large equal to 128oz ( 8 x 16 = 128 )

4 medium equal to 48oz ( 4 x 12 = 48

4 large equal to 64oz ( 4 x 16 = 64

12 medium equal to 144oz ( 12 x 12 = 144 )

Total of oz equal 384oz

384 - 80 = 304/80 = 3.8

3 more bowl of 80oz and 5 Mcup and 1/2 Scup

4 0
3 years ago
The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges $3604 to rent
agasfer [191]

Answer: 14 tons

$3,860.50

Step-by-step explanation:

Let x = the amount of sugar transported.

First company:

The cost is $3157 truck rental plus $50.25 per ton of sugar.

Total cost = 3157 + 50.25x dollars

Second company:

There is no charge for truck rental, but it costs $275.75 per ton of sugar.

The total cost is

275.75x

When the two costs are the same, then

275.75x = 3157 +50.25x

225.5x = 3157

x = 14 tons

The total cost is 275.75*14 = $3,860.50

5 0
3 years ago
Read 2 more answers
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
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