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3 years ago

Which expression can be used to find the value of x in the triangle shown?

Mathematics

1 answer:

Marina86 [1]3 years ago

6 0

The correct answer is A because you have to cross multiply x/20! Hope this helps!

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What is m-a = n+p, for a

sergeinik [125]

Answer:

A=m-n-p

Step-by-step explanation:

So solve for a, we have to isolate it on one side, so -a=n+p-m. So a=m-n-p

5 0

3 years ago

Read 2 more answers

Please answer within the next 7 min, giving 38 points of a ligament answer!

frosja888 [35]

The answer is choice C

6 0

3 years ago

Kunicki uses a medium and a large measuring cup to measure the ingredients to make his famous Buttery Oatmeal Raisin Cookies. He

Nonamiya [84]

Answer:

L = 16oz

M = 12oz

S = 8oz

Step-by-step explanation:

8 large equal to 128oz ( 8 x 16 = 128 )

4 medium equal to 48oz ( 4 x 12 = 48

4 large equal to 64oz ( 4 x 16 = 64

12 medium equal to 144oz ( 12 x 12 = 144 )

Total of oz equal 384oz

384 - 80 = 304/80 = 3.8

3 more bowl of 80oz and 5 Mcup and 1/2 Scup

4 0

3 years ago

The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges $3604 to rent

agasfer [191]

Answer: 14 tons

$3,860.50

Step-by-step explanation:

Let x = the amount of sugar transported.

First company:

The cost is $3157 truck rental plus $50.25 per ton of sugar.

Total cost = 3157 + 50.25x dollars

Second company:

There is no charge for truck rental, but it costs $275.75 per ton of sugar.

The total cost is

275.75x

When the two costs are the same, then

275.75x = 3157 +50.25x

225.5x = 3157

x = 14 tons

The total cost is 275.75*14 = $3,860.50

5 0

3 years ago

Read 2 more answers

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago