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bekas [8.4K]
3 years ago
13

A sewing machine sews at a constant rate of 1,500 stitches per minute. If the equation, y = 1,500x represents the relationship b

etween the number of minutes, x, and the total number of stitches, y, what is the independent and dependent variable? (EE.C.9b)​
Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

Step-by-step explanation:

x is the independent variable. y is the dependent variable.

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Look at the sequence : 5, -10, 20, -40, 80
Sphinxa [80]

Answer:

5 (5x1) , -10 -(5x2), 20(10x2), -40 -(20x2), 80(40x2)

so the next number should be previous number in the sequence multiplied by 2 and a negative sign.

-`(80x2) = -160


7 0
3 years ago
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What is the formula to find volume of regular objects?
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Answer:

B. 2x2

Step-by-step explanation:

5 0
2 years ago
Find the term to term rules for 2,6,18,54,162
faltersainse [42]

Answer:

a, ax3 =b, bx3= c , cx3=d, dx3=e

Step-by-step explanation:

2, 2×3=6, 6x3=18,18 x3 =54, 54x3= 162

Multiplication of three with previous number will give you next number in series.

4 0
2 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
3 years ago
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