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dem82 [27]
3 years ago
11

Write 1.0315x10^6 in standard form

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
<h3>1.0315×10⁶= 1.0315×1000000</h3><h3> = 1031500</h3><h3 /><h3>it is the standard form</h3><h3>1000000+000000+30000+1000+500+00+0</h3>

please mark this answer as brainlist

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Sloutions to y=x-4<br> (6,3)<br> (4,0)<br> (3,-1)<br> (2,-4)
Keith_Richards [23]
I hope this helps you



A) x=6 y=3 3=6-4 3=2 false



B) x=4 y=0 0=4-4 0=0 true


C) x=3 y=-1 -1=3-4 -1=-1 true


D) x=2 y =-4 -4=2-4 -4=-2 false
3 0
2 years ago
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Answer:

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1 year ago
The marketing department of a sports supply store wants to estimate the percentage of adults in the town who belong to a gym. Wh
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Since we want to estimate the percentage of adults in the town who belong to a gym. We should take a random sample from the town itself because a store’s adult customers, or their friends, or first 20 customers every day for one week, or adults at the local park might not represent better sample for survey.

Therefore, Take a random sample of adults in the town, and ask each person whether he or she belongs to a gym. Calculate the percentage of the total who say “yes.”

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7 0
2 years ago
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8 0
3 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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5 0
3 years ago
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