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3 years ago

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Write 1.0315x10^6 in standard form

1 answer:

lapo4ka [179]3 years ago

5 0

<h3>1.0315×10⁶= 1.0315×1000000</h3><h3> = 1031500</h3><h3 /><h3>it is the standard form</h3><h3>1000000+000000+30000+1000+500+00+0</h3>

please mark this answer as brainlist

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If g(x) = 2x - 5 and h(x) = 3x + 7, then g(h(x)) = ?

lana [24]

Step-by-step explanation:

$g(x) = 2x - 5$

$h(x) = 3x + 7$

To determine $g(h(x))$ , wherever you see an $x$ in $g(x)$ , replace it with the equation $h(x)$ :

$g(x) = 2x - 5$

$g(h(x)) = 2(h(x)) - 5$

$g(h(x)) = 2(3x + 7) - 5$

$g(h(x)) = 6x + 14 - 5$

$g(h(x)) = 6x + 9$

8 0

3 years ago

Irina-Kira [14]

1. 5x/2 +y=-3
2. False
3. y= -5x-37 because y=mx-b
4. y= 1/5 x - 1 because y=mx-b
M= the slope and b represents the intercept.

5 0

4 years ago

The population of big cats in Africa is increasing at a rate of 5% per year. At the

sesenic [268]

Answer:

a) 10,500 big cats

b) 13,401 big cats

c) 33 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t

Where:

p = original population

r = growing rate (decimal form; 5/100= 0.05)

t= years

A = population after t years

Replacing with the values given:

a) At 2005, 1 year passed since 2004 (t=1)

A = 10,000 (1+ 0.05)^1

A = 10,500 big cats

b)

At 2010, 6 years passed since 2004 (2010-2004= 6)

A = 10,000 (1+ 0.05)^6

A = 13,401 big cats

c)

50,000 < 10,000 (1+ 0.05)^t

Solving for t:

50,000/10,000 < 1.05^t

5 < 1.05^t

log 5 < log 1.05^t

log 5 < t ( log 1.05)

log 5 / log 1.05 < t

32.9 years < t

33 years = t

Feel free to ask for more if needed or if you did not understand something.

6 0

3 years ago

Define a sequence by a1=3 and an=3an−1. Find the first four terms of the sequence. Give a simplified integer answer.

aalyn [17]

Answer:

The first four terms are 3,9,27,81

Step-by-step explanation:

<u>Step :-1</u>

Given first term of sequence is $a_{1} = 3$

Given 'n' t h term is $a_{n} = 3 a_{n-1}$ .............(1)

here we put n = 2 in equation (1)

$a_{2} = 3a_{2-1}$

$a_{2} = 3 a_{1}$ ..............2

put $a_{1} = 3$ in equation (2)

$a_{2} = 3(3)$

$a_{2} = 9$

put n=3 in equation (1)

$a_{3} = 3 a_{3-1}$

$a_{3} = 3a_{2}$

$a_{3} = 3 (9) = 27$

put n= 4 in equation (1)

$a_{4} = 3 a_{4-1}$

$a_{4} = 3 a_{3}$

$a_{4} = 3(27) = 81$

The first four terms of the sequence is

3 , 9, 27 , 81 ....this is geometric sequence

a =3 and ratio term is r =3

6 0

3 years ago

A researcher takes a simple random sample of 83 homes in a city and finds that the mean square footage is 1628 with a standard d

Anna [14]

Answer: (1583.63, 1672.37)

Step-by-step explanation:

Given : Sample size : n= 83

Sample mean : $\overline{x}=1628$

Sample standard deviation : $\sigma=243$

The population standard deviation $(\sigma)$ is unknown .

The confidence interval for population mean :

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$

For 90% confidence , significance level = $\alpha=1-0.90=0.10$

Using t-distribution table , Critical t-value = $t_{(\alpha/2, n-1)}=t_{0.05,82}=1.6636$

, where n-1 is the degree of freedom.

Now , 90% confidence interval for the mean square footage of all the homes in that city will be :-

$1628\pm (1.6636)\dfrac{243}{\sqrt{83}}\\\\ 1628\pm (1.6636)(26.672715)\\\\\\\\\approx1628\pm 44.37\\\\=(1628- 44.37,\ 1628+ 44.37)\\\\=(1583.63,\ 1672.37)$

Hence, the 90% confidence interval for the mean square footage of all the homes in that city = (1583.63, 1672.37)

7 0

3 years ago