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3 years ago

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I am a type a person who likes d cups will do anything to touch a d cup doesn't care what other people say about me and only lik

es c cups that are cute

2 answers:

Sloan [31]3 years ago

7 0

I know right, lol. ;)

faust18 [17]3 years ago

3 0

Answer: mmm I don’t even understand what you trying to say but this doesn’t look like a question to me, is this even a question just saying

Step-by-step explanation:

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From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.

zhenek [66]

1.3/13(if you mean jacks queens and kings)
2.1/52
3.1/2
4.1/13
5.1/4

8 0

3 years ago

Read 2 more answers

G = (5,-10),(25,-50),(50,100)

Murrr4er [49]

This is the answer not sure if you wanted it graph or not

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3 years ago

Find the value of x by filling in the blanks in the provided statement- reason solution

fgiga [73]

Answer/Step-by-step explanation:

Given:

m<MNQ = 132°

m<Q = 54°

m<P = 3x

1. m<MNQ = m<P + m<Q

Reason: exterior angle theorem of a triangle

Plug in the values

2. 132° = 3x + 54°

Reason: Substitution

3. x = 26

Reason: Algebra

132 - 54 = 3x (substraction property of equality)

78 = 3x

78/3 = x (division property of equality)

26 = x

x = 26

3 0

3 years ago

What is the HCF of 30 and 50 <br><br> Pls I need this

Tom [10]

10
Therefore, the greatest common factor of 30 and 50 is 10.

8 0

2 years ago

Read 2 more answers

What’s the 5th term is 2,14,98

iragen [17]

$\bold{\huge{\orange{\underline{ Solution }}}}$

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

$\sf{ 2 , 14 ,.... 98 }$
<u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

$\sf{a1\: or \:1st\: term = 2 }$
$\sf{a2 \:or \:2nd\: term = 14 }$
$\sf{an \:or\: last\: term = 98}$

<u>Here</u><u>, </u>

Common difference of an AP

$\sf{ a2 - a1 }$

$\sf{ = 14 - 2}$

$\sf{ = 12}$

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

$\sf{an = a1 + ( n - 1 )d}$

$\sf{a5 = 2 + ( 5 - 1 )12}$

$\sf{a5 = 2 + 4 × 12}$

$\sf{a5 = 2 + 48}$

$\sf{\red{a5 = 50}}$

Hence, The 5th term of given AP is 50

4 0

2 years ago