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Mrrafil [7]
4 years ago
5

Which algebraic expressions are polynomials? Check all that apply. 2x3 – x3y – 3x2 + 6x y2 + 5y – 2 – –x –x3 – x2 +

Mathematics
2 answers:
Artemon [7]4 years ago
8 0

Answer: The answer is y^2+5y-2~~~\textup{and}~~~-x-x^3-x^2.



Step-by-step explanation: We are all familiar with the concept of polynomials.  A polynomial is an algebraic expression involving an unknown variable and its positive integral powers.

Therefore, from this definition of a polynomial, we can conclude any algebraic polynomial consisting of more than one unknown variable will not be considered as a polynomial.

Thus, out of the given options, the following are polynomials.

y^2+5y-2~~~\textup{and}~~~-x-x^3-x^2.


alexira [117]4 years ago
3 0

Answer:

B C E F!

Step-by-step explanation:

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Two companies have sent representatives to an industry conference. The first company sent 12 representatives and the second comp
podryga [215]

Answer:

0.1289

Step-by-step explanation:

Given that two companies have sent representatives to an industry conference.  

The first company sent 12 representatives and the second company sent 20 representatives

Selecting any 22 out of these 32 can be done in 32C22 ==\frac{32!}{(22!(32−22)!)} \\= 64512240

Favourable outcomes = No of ways of selecting 10 from I and 12 from II

= 12C10(20C12) =66(125970) \\=8314020

Probability required = \frac{8314020}{64512240} \\=0.1289

5 0
3 years ago
Which if the following is the equation of a line that passes through the points (2,5) and (4,3)
Taya2010 [7]
Hi there!

First, let's find the slope of the two points using the slope formula (y2 - y1 / x2 - x1).

S = 4 - 2 / 3 - 5
S = 2 / -2
S = -1

Next, we'll plug in the slope and a point into point-slope form (y - y1 = s(x - x1)) in order to find an equation. I will show the work using both points, which will result in two different equations.

(2,5)
y - 5 = -1(x - 2)
y - 5 = -x + 2
y = -x + 7

(4,3)
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7

The two equations came out the same! Which is completely okay, and happens sometimes. 

Hope this helps!! :)
If there's anything else that you're needing help with, don't be afraid to reach out!


3 0
4 years ago
25 POINTS!!!
Alex

Answer:

a triangular prism net has two rectangular bases and triangular faces, a square pyramid has a square base and the faces are triangular, a cube has all squares, and a rectangular prism has rectangular bases and rectangular faces

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches
Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}

OK.

3 0
3 years ago
1 .Find the decimal expansion of 7/8
saw5 [17]

Answer:

the decimal expansion of 7/8 is

0.875

6 0
3 years ago
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