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erastovalidia [21]
3 years ago
7

Silvergrove middle school spent $60 to purchase 4 work books. How many these workbooks can they buy for $90? Solve using unit ra

tes.
Mathematics
1 answer:
cluponka [151]3 years ago
6 0
They can buy 6 workbooks with $90. To find the unit rate we simply divide the cost ($60) by the number of books (4). That gives us $15, the cost of 1 workbook. So now to find out how many workbooks can be purchased with $90, we divide 90 by 15. That’s how I got 6 workbooks. Hope this helps.
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7x-2y=-5which ordered pair is a solution of the equation
sashaice [31]

Answer:

What ordered pair my closest answer is y = 5/2+7x/2

Step-by-step explanation:

Subtract 7x from both sides of the equation.

3 0
3 years ago
What are the solutions to the system of equations? y=x2−5x−6 y=2x−6
Leya [2.2K]

Answer:

I graphed both equations to find the solutions.

Step-by-step explanation:

When x is 0, y is -6. When x is 7, y is 8.

x = 0 and 7

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This is asking “identity whether each of the following is a linear function” please ignore the quality tho. The question numbers
Svetlanka [38]

Answer:

4. Yes 5.No 6. No

Step-by-step explanation:

To be short,a linear equation has a coefficient of only 1 degree.

If the degree is over 1 it isn't a linear equation.

4 is the linear equation since it x value 7x has a degree of 1.

5 isn't becuase it's x value has a degree of 5

6 isn't becuase it degree is 4.

7 0
3 years ago
A number is added to the square of itself and the result is 90. Find all possible values for the number
kolezko [41]

Answer: 9

Step-by-step explanation: 9 x 9 equals 81 and 81 add 9 is 90

6 0
3 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
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