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Romashka-Z-Leto [24]
3 years ago
13

Take 25 points please help me!!!!one example,for the matrix skew-Hermitian​

Mathematics
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

Una matriz hermitiana, o también llamada matriz hermítica, es una matriz cuadrada con números complejos que tiene la característica de ser igual a su traspuesta conjugada.

A=A^*  

Donde A^* es la matriz traspuesta conjugada de A.

Step-by-step explanation

Ejemplo de matriz hermitiana de orden 2×2

₍ 5.............  3+7i₎

₍3-7i .............2

₎

Ejemplo de matriz hermitiana de dimensión 3×3

(3............2-i......-5i)

(2+i............0.....9-5i)

(5i.........9+5i.....6)

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Hi pls answer correctly thank you :)
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Answer: The answer is C.

Step-by-step explanation: This is because reflecting a point from Quadrant 1 over the y-axis always gets you a result from Quadrant 2.

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Mario compared the slope of the function graphed below to the slope of the linear function that has an x-intercept of 1 and a y-
Lelu [443]

Answer:

The slope of the function graphed is less than the linear function that has an x-intercept of 1 and a y-intercept of -2.

Step-by-step explanation:

It is given that x-intercept is 1 and y-intercept is -2.

Now, the coordinate of the point is (1,0) and (0,-2).

We know that,

Slope = \dfrac{y_2-y_1}{x_2-x_1}

S_1=\dfrac{-2-0}{0-1}

S_1 = \dfrac{-2}{-1}

S_1=2

Now, Slope of the graph given

Co-ordinate is (-5,0) and (1,2).

Using the formula of slope

S_2 = \dfrac{2-0}{1-(-1)}

S_2 = \dfrac{2}{1+1}

S_2 = \dfrac{2}{2}

S_2 =1

Now, S_1>S_2

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The original price of the sweater Taylor purchased was $44. The store was
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3 years ago
How many integers between 2020 and 2400 have four distinct digits arranged in increasing order?
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Answer:  E=15

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

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