The five men would be paid $10.41 each at the same hourly rate
<u>X - Intercept</u>
x + 3y + 2z = 6
x + 3(0) + 2(0) = 6
x + 0 + 0 = 6
x + 0 = 6
<u> - 0 - 0</u>
x = 6
X - Intercept: (6, 0, 0)
<u>Y - Intercept</u>
x + 3y + 2z = 6
0 + 3y + 2(0) = 6
0 + 3y + 0 = 6
0 + 0 + 3y = 6
0 + 3y = 6
<u>- 0 - 0</u>
<u>3y</u> = <u>6</u>
3 3
y = 2
Y - Intercept: (0, 2, 0)
<u>Z - Intercept</u>
x + 3y + 2z = 6
0 + 3(0) 2z = 6
0 + 0 + 2z = 6
0 + 2z = 6
<u>- 0 - 0</u>
<u>2z</u> = <u>6</u>
2 2
z = 3
Z - Intercept: (0, 0, 3)
<u>Volume of the X - Intercept, Y - Intercept, and Z - Intercept</u>
V = ¹/₃(¹/₂lwh)
V = ¹/₃(¹/₂(6)(2)(3))
V = ¹/₃(¹/₂(12)(3))
V = ¹/₃(¹/₂(36))
V = ¹/₃(18)
V = 6 u³
First, we need to find the missing leg of triangle ACD. We have to use pythagorean theorem to find the missing leg.
a^2 + b^2 = c^2
In this problem,
a = 2
b = ?
c = 5
Plug our numbers into the formula above.
2^2 + b^2 = 5^2
Simplify our terms
4 + b^2 = 25
Subtract 4 from both sides
b^2 = 21
Take the square root of each side
b = √(21)
Now, we can solve for the area of triangle ABC
Area of a triangle = (h * b) / 2
h = height
b = base
In this problem,
h = √(21)
b = 5.0
Plug our numbers into the area formula of a triangle
Area = (√(21) * 5) / 2 = 11.46 square units
