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Morgarella [4.7K]
3 years ago
8

James's Sister is arranging rows of beads. She has 56 yellow beads and 120 blue beads. She wants to arrange them so that all the

beads in a row are, are the same color, and so that each row has the same number of beads. What is the least number of rows James's sister can make?
Mathematics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

22

Step-by-step explanation:

gcf 56, 120 = 8, 56/8=7, 120/8=15, 7+15=22. 22

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78cm

Step-by-step explanation:

d = 10

area of a circle = πr^2

22/7 × 5 × 5

78.5cm

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Find the point of intersection (if any) of the following pairs of lines: a) x – 2y +1=0 2x + 3y – 7 = 0 b) x-2y+11=0 -x+2y-13 =
pychu [463]

Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

2x + 3y - 7 = 0

To find the point of intersection, we need to solve the system of equations  and the result will be the point of intersection (x,y)

x-2y+1=0\\x= 2y-1

Now we substitute x in the second equation:

2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7

Now we substitute y in our first equation.

x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7.

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

-x + 2y - 13 =0

We are going to follow the same procedure:

x-2y+11=0\\x=2y-11

-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0
3 years ago
Can someone help me with this question? Thank you!
Harrizon [31]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

The given expression is :

\qquad \sf  \dashrightarrow \:4x + 8

plug the value of x as 3

\qquad \sf  \dashrightarrow \:4(3) + 8

\qquad \sf  \dashrightarrow \:12 + 8

\qquad \sf  \dashrightarrow \:20

Therefore, the required value is 20

8 0
2 years ago
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