Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30
substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w
substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w
substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15
insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16
B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2
Answer:
1) The 38th term is A. 38
2) The 11th term is D. 3072
3) The 3rd term is C. 34
Step-by-step explanation:
1) I added 2 until I got to the 38th term.
2) I multiplied until I got to the 11th term.
3) I added 3 until i got to the 12th term.
The teacher showed a more complex way to do it but this is just what I did.
I took the quiz, so I know that I got them all correct.
Last one bc it jus is the last one so put in the last one bc the last one is the right one
61 is the composite Number your welcome
Answer:
Step-by-step explanation:
4x + 16xy
GCF is 4x
4x(1 + 4y) <===== this is the correct one
