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Yuliya22 [10]
3 years ago
12

Which expression is equivalent to 5(c + 2(c+d)

Mathematics
1 answer:
Fofino [41]3 years ago
5 0
15c+10d that’s the answer
You might be interested in
6 - 1\6? I am confused.
vladimir2022 [97]
Okie, so you have an whole number subtracted by a fraction of a number. The way to approach this problem is to convert whole number to the LCD (least common denominator) of the fraction. In this case it would be 6.
6 would be 36/6 (same number just different form)
now just subtract the numerators over the denominator
(36-1)/6 = 35 / 6 is your answer as an improper fraction. As a mixed number, it would be 5 5/6.
I hope this helps :-)
6 0
3 years ago
Read 2 more answers
If the legs of an isosceles right triangle are 6 units long find the length of the hypotenuse
Degger [83]

Answer:

Length of the hypotenuse = 8.5 units

Step-by-step explanation:

Given the length of the sides of an isosceles right triangle to be 6units

Hint: an hypotenuse is the longest line

To solve this, we use Pythagoras rule

Hypotenuse^2 = adjacent ^2 + opposite ^2

Adjacent = opposite = 6

Let our hypotenuse to be a

a^2 = 6^2 + 6^2

a^2 = 36 +36

a^2 = 72

To get a, let's find the square root of 72

a = 8.485 unit

Therefore, the length of the hypotenuse = 8.5 units

8 0
3 years ago
1. Find the derivative with respect to x of x +1/x from first principle. <br>​
Murrr4er [49]

If you mean f(x)=x+\frac1x, then the derivative is

\displaystyle f'(x) = \lim_{h\to0} \frac{\left(x+h+\frac1{x+h}\right) - \left(x+\frac1x\right)}h \\\\ = \lim_{h\to0} \frac{(x+h)-x}h + \lim_{h\to0} \frac{\frac1{x+h} - \frac1x}h \\\\ = \lim_{h\to0} \frac hh + \lim_{h\to0} \frac{x-(x+h)}{hx(x+h)} \\\\ = \lim_{h\to0} 1 - \lim_{h\to0} \frac h{hx(x+h)} \\\\ = 1 - \lim_{h\to0} \frac1{x(x+h)} \\\\ = \boxed{1 - \frac1{x^2}}

If you mean f(x) = \frac{x+1}x = 1 + \frac1x, we know from above that

\displaystyle \left(\frac1x\right)' = \lim_{h\to0} \frac{\frac1{x+h}-\frac1x}h = -\frac1{x^2}

which leaves the constant term, whose derivative is

\displaystyle (1)' = \lim_{h\to0}\frac{1 - 1}h = 0

and so

f'(x) = -\dfrac1{x^2}

6 0
2 years ago
Please answer this in two minutes
diamong [38]

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

\frac{XY}{sin(W)} = \frac{WY}{sin(X)}

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

\frac{XY}{sin(67)} = \frac{24}{sin(43)}

Cross multiply:

XY*sin(43) = 24*sin(67)

XY*0.68 = 24*0.92

Divide both sides by 0.68 to solve for XY

\frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68}

XY = 32.47

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

6 0
3 years ago
HELP QUICK PLSS
Snezhnost [94]

Answer:

pretty sure the tree's 20 feet

3 0
3 years ago
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