Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
Answer:
Step-by-step explanation:
as given j=h and k=m then which expression for g is
as from attached image , we can see that its look like two right angle triangle
so from lower triangle we apply the pythagorean theorem .
which state that sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.
so small triangle ΔEBD
h² +k²= g² ---------------(1)
now from big triangle ΔABC
(j + h)² +(m + h)² =f²---------(2)
given j=h and k=m so from equation-2 we can find ,
(h + h)² +(k+ k)² =f²
(2h)² +(2k)²=f²
4h²+ 4k²= f²
4(h²+k²)= f² ----------(3)
now from equation 1 and 3 we can obtained .
4×g² =f²
take square root both side we get,
2×g=f
so g=f/2----- Answer
Answer:
I am almost 100% sure that the answer is B. good luck on your test Ma'am
Step-by-step explanation:
Answer:
option b is correct answee