Answer:
True
Explanation:
In Object Oriented Programming, a constructor is a type of subroutine whose purpose is to create an object.
when the constructor is called, it initializes the data members of the object and establishes the invariant of the class.
Some important concepts:
Data members: The data members are the data encapsulated within the object (e.g. int hour for the variable <em>'hour'</em> in an object called <em>'date'</em>)
Invariant of the class: The class invariant is the invariant used to constrain the object (e.g. values between 0 and 24 for the variable <em>'hour'</em>)
255.255.240.0 is a /20 subnet mask, therefore there are 4 borrowed bits (from the 3rd octet). Number of hosts on each subnetwork = (2 to the power 4) - 2 (i.e. 4 bits in host portion of address), which gives 14. So I got 16 subnetworks, and 14 hosts on each subnetwork.1
Answer:
speed(0)
penup()
setposition(-200,-200)
pendown()
def draw_square_row():
color_value = 0
for i in range (10):
if color_value %2 == 0:
begin_fill()
color("red")
for i in range (4):
forward(40)
left(90)
forward(40)
color_value = color_value + 1
end_fill()
elif color_value %2 == 1:
begin_fill()
color("black")
for i in range (4):
forward(40)
left(90)
forward(40)
color_value = color_value + 1
end_fill()
def draw_square_row_2():
color_value = 1
for i in range (10):
if color_value %2 == 0:
begin_fill()
color("red")
for i in range (4):
forward(40)
left(90)
forward(40)
color_value = color_value + 1
end_fill()
elif color_value %2 == 1:
begin_fill()
color("black")
for i in range (4):
forward(40)
left(90)
forward(40)
color_value = color_value + 1
end_fill()
def move_up_a_row():
left(90)
forward(40)
right(90)
backward(400)
for i in range (5):
draw_square_row()
move_up_a_row()
draw_square_row_2()
move_up_a_row()
Explanation:
tell me if you get it right
Answer:
string=""
while string not in {"Quit","quit","q"}:
string=input("Enter line to be reversed") #line of text will be entered
if string!="Quit" and string!="quit" and string!="q": #If quit is not entered
print("Reverse of line is : ")
print(string[::-1])
OUTPUT :
Enter line to be reversedThis code is in python language
Reverse of line is :
egaugnal nohtyp ni si edoc sihT
Enter line to be reversedHello world
Reverse of line is :
dlrow olleH
Enter line to be reversedquit
Explanation:In the above program, First a while loop is executed and checked if line of text is not 'quit', 'Quit' or 'q'. If condition is true, then loop is executed and in python any string or list can be traversed from end if step is given -1. Similarly line of text is accessed from the last element. If quit is entered, then the program will be broken out of the loop.
So the question ask on which of the following among the choices might happen if dispatchable threads were removed from the software hierarchy and the best answer among your choices is letter D. Background program would be dropped. I hope you are satisfied with your answer
