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Rzqust [24]
3 years ago
14

the length of a Ribbon is 11.55 metre if it is cut into pieces and divided equally among 7 Girls how much ribbon will each get f

ind​
Mathematics
2 answers:
Gelneren [198K]3 years ago
5 0

Answer:

1.65 meters

Step-by-step explanation:

11.55 meters divided by 7 is 1.65 meters

oksian1 [2.3K]3 years ago
3 0

Answer:

1.65 metres per girl

Step-by-step explanation:

Divide 11.55 (length) of ribbon by 7 girls (11.55/7). You get 1.65 metres.

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3 years ago
The difference of a number x and 4 is 3
Kruka [31]
"the difference of a number x and 4": x - 4
"is": =
"3": 3

Combine the terms so that it looks like the sentence numerically:

"the difference of a number x and 4 is 3": x - 3 = 4

x - 3 = 4 is your answer.

To solve for x:

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Add 3 to both sides.

x - 3 = 4

x -3 (-3) = 4 (-3)

x = 4 - 3

x = 1

1 is your answer for x.

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6 0
3 years ago
Rick has 1/2 of a footlong sub left from yesterday. He ate 1/3 of the leftover sandwich as a snack. What fraction of the entire
Alecsey [184]

Answer:2/6

Step-by-step explanation: because 1+1=2 and then  you find the lcm of 2and3 then u get your aanswer

6 0
3 years ago
Giselle's youth club sells cookies to fund their trips and activities. Each year they need to earn $1,247 from selling cookies.
algol [13]

Price per box, P = $1.45 .

Money left, M = $1247 - $472.70 = $774.3  .

Let, number of boxes are x.

So,

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Therefore, they have to sell 534 more boxes.

Hence, this is the required solution.

6 0
3 years ago
Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f
sergeinik [125]
f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\
\hbox{statement 1 is false} \\ \\
f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\
f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8
\\ f(-2)=f(2) \\
\hbox{statement 2 is true}

f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\
f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\
71+8 \not= 143 \\
f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\
f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\
71 \times 8 \not= 296 \\
f(5) \times f(2) \not= f(10) \\
\hbox{statement 4 is false}

Stamement 2. f(-2)=f(2) is true.
3 0
3 years ago
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