Answer:
9
Explanation:
Another way to represent this question is:
+ AB BA1A2
In the one's column, B and A add to produce a number with a two in the one's place. In the ten's column, we can see that a one must carry in order to get a digit in the hundred's place. Together, we can combine these deductions to see that the sum of A and B must be twelve (a one in the ten's place and a two in the one's place).
In the one's column: B+A=12
The one carries to the ten's column.
In the ten's column: (1)+A+B=(1)+12=13
The three goes into the answer and the one carries to the hundred's place. The final answer is 132. From this, we can see that A=3 because 1A2=132.
Using this information, we can solve for B.
A+B=12 and A=3
3+B=12
B=9
