Answer:
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Step-by-step explanation:
Answer:
Step-by-step explanation:
498/26 = 19 with a remainder of 3
so each group will have nineteen students but you need 22 more to make all groups have 20 students
498 + 22 = 520
520/26= 20
Answer:
see below
Step-by-step explanation:
It looks like all you're asking for is to copy the data from the problem statement to a chart. The chart is attached.