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1 answer:
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Answer:
0.017559
Step-by-step explanation:
Data provided:
Probability of Households Having cable TV, p₀ = 76% = 0.76
Therefore,
The probability that the Households not having cable TV = 1 - 0.76 = 0.24
Sample size, n = 225 households
sample proportions is less than 82% i.e p = 0.82
Now,
The standard error, SE =
or
SE =
or
SE = 0.02847
and,
or
or
Z = 2.107
therefore,
P(sample porportions < 0.82) = P(Z < 2.107)
now from the p value from the Z table
we get
P(sample porportions < 0.82) = 0.017559