The answer is B
All liner lines are straight, and have one slope.
Answer:
D
Step-by-step explanation:
Answer:
2.5
Step-by-step explanation:
8 -48 = 3 +13
*ADD 48 from each side(so -48+48=0 and 13+48=61)
8 = 3 +61
*Subtract from each side(so 3-3=0 and 8-3=5)
5 = 61
*Now u divide 5/5=1 and 61/5=2.5
Answer:
Step-by-step explanation:
Keep in mind that the tangent function is negative in Quadrants II and IV.
Of the three possible answers, the 2nd is invalid because the tangent is positive in Q III.
If the reference angle were in Quadrant II and had the value 30° (second possible answer), then the opposite side would be +1, the adjacent side -√3 and the hypotenuse 2. Based on this, the tangent of theta would be opp / adj, or +1 / (-√3) or -√3/3. This is correct.
First:
A graph that starts y< or y> will always be a dashed line, because the points on the line do not make the equality true.
A graph with y≤ or y≥ will have a solid line.
Second,:
If the equation is y<, then the shading will be below the line. (If you were standing on the line, you'd look straight down for the solutions.)
If the equation is y>, then the shading will be above the line. (If you were standing on the line, you'd look straight up for the solutions.)
For your exercise:
Neither A nor B fits that inequality. I hope there are options C and D