Answer: The vertex of the parabola (quadratic function) is (-2,-4)
Fourth option: (-2,-4)
Solution:
y=x^2+4x
y=ax^2+bx+c; a=1, b=4, c=0
Vertex: V=(h,k)
h=-b/(2a)
h=-4/(2(1))
h=-4/2
h=-2
y=x^2+4x
k=y=h^2+4h
k=(-2)^2+4(-2)
k=4-8
k=-4
Vertex: V=(h,k)
Vertex: V=( -2, -4)
Answer:
10
, or 17.32050
Step-by-step explanation:
Answer:
The vertex of the function is (5,6).
Step-by-step explanation:
The equation is already written in vertex form. Given a quadratic function with a vertex of (h,k), the equation for the graph is y=a(x-h)^2+k.
We can extract h and k from the provided equation and get the point (5,6)
First, plot the y-intercept which is 150. So, plot the point (0,150).
Then, just input values of x into the equation.
Use the value of x you input and y value you got after solving into (x,y) and plot the point.
