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Tju [1.3M]
2 years ago
13

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

e given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+193x+128
Mathematics
1 answer:
Alex_Xolod [135]2 years ago
4 0

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation

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An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B. Eight random graduates from c
Karolina [17]

Answer:

Calculated value t =  0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

<u>Step-by-step explanation:</u>

<u>we will t-test </u> t = x⁻- y⁻ /S√ n₁+n₂-2

Given An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B

course A type at 62, 85, 59, 64, 73, 70, 75, and 72

mean of x is x⁻ = ∑x / n

mean of x = 62+85+59+64+73+70+75+ 72 /8 = 70

x⁻ = 70

course B type at 75, 64, 81, 55, 69, and 58

mean of y is  y⁻ = ∑y / n = 75+64+81+55+69+ 58/6 = 67

y⁻ =67

course A    course B

    x                    y             x- x⁻     (x-x⁻ )^2     y- y⁻     (y-y⁻ )^2    

    62                75            8             64          8            64

    85                64           15            225       -3             9

    59                81           -11            121          14            196      

    64                55           -6            36          -12          144          

    73                69          3                9            2            4

    70               58            0              0           -9            81

    75                              5              25

    72                              2               4

                                            ∑( (x-x⁻ )^2= 484           ∑( (y-y⁻ )^2= 498

Adding ∑( (x-x⁻ )^2+ ∑( (y-y⁻ )^2= 982

n₁+n₂-2 = 8+6-2=12

now S^2 =  982/ 12 =81.833

<u>Null hypothesis :H₀:μ₁=μ₂ ( there is no difference between A and B)</u>

<u>Alternative hypothesis :H₁:μ₁≠μ₂</u>

<u>level of significance ∝=0.05</u>

<u>we will use t-test </u> t =   0.614 ( see attachment )

The degrees of freedom = n₁+n₂-2 = 8+6-2=12

From tabulated value  t = 1.782

Calculated value t = 0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

There is no difference between Course A and Course B

Download docx
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Answer:

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Answer:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

Step-by-step explanation:

we are given a function

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we would like to simplify it for h(-1)

in order to do so

substitute the value of x

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2}  + 8}

by order of PEMDAS

simplify square:

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { ( 1)}^{}  + 8}

simplify multiplication:

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simplify addition:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{12}

simplify subtraction:

\displaystyle \sf h( - 1) =  \frac{   - 8}{12}

reduce fraction:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

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3 years ago
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