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3 years ago

Please answer. I asked like four times I need this before 11 ;;—-;;

Mathematics

1 answer:

svet-max [94.6K]3 years ago

7 0

Answer:It takes 250 g of pasta and 240 ml of sauce to make one batch of spaghetti and it takes 600g of pasta and 700ml of sauce to make one batch of lasagna.

Case 1: Pasta

The chef wants to make spaghetti and lasagna using more than 4000 g of pasta.

S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.

So the equation becomes :

Case 2: Sauce

chef wants to make spaghetti and lasagna using more than 5000 ml of sauce.

S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.

So the equation becomes:

Answer :

The two equations are :

For pasta:

For sauce:

Step-by-step explanation:

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A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

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2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

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$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

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4 years ago