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Reika [66]
3 years ago
7

Find the length of AB

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
X=3
that is the answer
olasank [31]3 years ago
6 0

Answer:

AB is 15

Step-by-step explanation:

AB and BC are equal because the line that goes through the triangle is going through at a 90 degree angle, u can see that by the small square, and u know it's in the middle bc of the short lines on AD and DC, the short lines means that they are congruent, so:

5x = 4x + 3

subtract 4x from both sides

x = 3

Now u have x, put it in the equation

5x = 5(3) = 15

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What is the value of y in y-5=3-9(y+2)
Irina18 [472]
Y-5=3-9(y+2). so so u are going to distribute-9 to y and 2 which is -9y-18

so u are going to add like terms 3 and -18 which is -15. so the next step is going to be y-5=-9y-15 so u are going to add 5 to -5 and -15 to balance the equation and u will get -10 .  y=-9y -10. since u are multiplying -9 by y so have to expand it y= -9 * y -10. so u have to divide y by y to get y . -9-10= -19 soo y =-19


3 0
3 years ago
How can we find how many inches wide the coat box is?
Alex777 [14]

Answer:

First we found the sum of 15.438 and 3.18. The subtract the answer from 32.476.

Option A is correct.

Step-by-step explanation:

The total width of box is = 32.476

Width of box of T-shirts = 15.438

Width of box of Socks = 3.18

We need to find width of coat box.

The width of coat box can be found as:

Total Width = Width of box of T-shirts + Width of box of Socks + width of coat box

32.476 = 15.438 + 3.18 + width of coat box

32.476 = 18.618 + width of coat box

width of coat box= 32.476 - 18.618

width of coat box = 13.858

So, The Width of coat box = 13.858 inches

First we found the sum of 15.438 and 3.18. The subtract the answer from 32.476.

Option A is correct.

5 0
3 years ago
Allocate an array of 100 integer pointers and assign the resulting pointer to the appropriately declared variable, ip_arr. alloc
Marina86 [1]

the code is in word file below attached

Download docx
4 0
3 years ago
Jay has two boards. The length of the first board is 1 and 2-thirds feet, and the length of the second board is 5-eighths foot.
LekaFEV [45]
She is not correct, since the combined length of both boards is more than 2 feet
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3 years ago
Accomplished silver workers in india can pound silver into incredibly thin sheets, as thin as 3.00 10-7 m (about one-hundredth o
Vlad1618 [11]

The density of silver is 10,500 kg/m^3, therefore the volume of a 2.90 kg silver is:

V = 2.90 kg / (10,500 kg/m^3)

V = 0.000276 m^3

 

We know that volume is simply area times height:

Volume = Area * height

 

SO the area is:

Area = 0.000276 m^3 / 3.00 x 10-7 m

<span>Area = 920.63 m^2</span>

7 0
3 years ago
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