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kifflom [539]
3 years ago
10

Y> - 1/2 x + 3

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

0,3

Step-by-step explanation:

enter in a graphing calculator see where you hits 0

ELEN [110]3 years ago
4 0

Answer:

the answer is 0,3

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I’m confused on this one
Digiron [165]

first, you would find the sum of all the other angles.

85+115+50 = 250

knowing that the circumference of a circle is 360, you can subtract 250 from 360. which leaves you with 110. hopefully this is correct

8 0
3 years ago
For what integer value of x is 3x+5>11 and x-3 <1?
Andre45 [30]
3x + 5 > 11
3x + (5 - 5) > 11 - 5 
3x > 6
3x / 3 > 6 / 3
x > 2

x - 3 < 1
x (-3 + 3) < 1 + 3
x < 4

When subtracting / adding values to both sides, the inequality does not change.

When multiplying / dividing by a positive value, the inequality also doesn't change, but when multiplying , dividing with a negative value, the inequality must be flipped.
7 0
3 years ago
Ariel's guitar teacher charged $35 each month for lessons. Her new rate is $40 a month.
Aleks04 [339]

Answer:

$20

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
A store owner purchases thirty 75-watt light bulbs and 40 fluorescent light bulbs for a total cost of $95. A second purchase, at
N76 [4]

Answer:   75-watt are 30$  fluorescent are 30$ in the second and 65$ in the first

     

Step-by-step explanation: i calculated thirty 75-watt and the fluorescent and got these kinda hard to explain hope i helped:)

7 0
3 years ago
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