I think it’s b don’t trust me though I did that stuff last year
OK we have a right angle A and we're interested in angle B.
Relative to B, AB=7 is the adjacent side and AC=17 is the opposite side so we have:
![\tan B = \dfrac{\textrm{opp}}{\textrm{adj}} = \dfrac{17}{7}](https://tex.z-dn.net/?f=%5Ctan%20B%20%3D%20%5Cdfrac%7B%5Ctextrm%7Bopp%7D%7D%7B%5Ctextrm%7Badj%7D%7D%20%3D%20%5Cdfrac%7B17%7D%7B7%7D)
![B = \arctan \frac{17}{7} \approx 67.62 ^\circ](https://tex.z-dn.net/?f=B%20%3D%20%5Carctan%20%5Cfrac%7B17%7D%7B7%7D%20%5Capprox%2067.62%20%5E%5Ccirc)
Answer: 68
Hm... okay so what i got was A = B+5/2 because that is the only one that fits.
Given the original dimensions above which is 3ft and 4ft, the area of the painting on a canvass would be 12ft. Since Linda wants to double the area of the display model, this makes the doubled area 24ft. So in order to get this area, Linda should add 1.4 feet to both the length and the width, making the dimensions 4.4ft and 5.4ft. Multiply both and you get 23.76ft or to round it off, 24 feet. Hope this answers the question.