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Mathematics

1 answer:

I am Lyosha [343]2 years ago

6 0

The answer is 81 feet. This is because the maximum height is the y-value of the vertex since the vertex is the maximum point. So, it is 81 feet

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A restaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If

Fiesta28 [93]

X = number of servers
y = number of guests

$\text {number of guest per table = } 4$ 

 $\text {number of tables = } \dfrac{y}{4}$

 $\text {number of servers needed = } \dfrac{y}{4} \div 12$ 

 $\text {number of servers needed = } \dfrac{y}{4} \times \dfrac{1}{12}$

$\text {number of servers needed = } \dfrac{y}{48}$

There must be at least 1 server for every 12 tables:
$x \geq \dfrac{y}{48}$

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3 years ago

Jacobs & Johnson, an accounting firm, employs 19 accountants, of whom 7 are CPAs. If a delegation of 2 accountants is random

Sergio039 [100]

Answer:

0.003

Step-by-step explanation:

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3 years ago

What is the value of the expression?? PLEASE HELPPPPP

ycow [4]

Answer:

Step-by-step explanation:

= -4 x (-5) - 2

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= 18

5 0

3 years ago

Read 2 more answers

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$