It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
Answer: Y=3, X=5
Step-by-step explanation:
2(2y-1) + 3y=19
4y-2+ 3y=19
7y=21
Y=3
Plug in y in the second equals
X=2(3) -1
X=6-1
X=5
Hope this helps!
Answer:
Step-by-step explanation:
- -13x < 65
- x > - 65/13
- x > -5
- x = (-5, + oo)
Answer:
D) 20.
Step-by-step explanation:
First find the value of x using Pythagoras theorem:
10^2 = x^2 + (2x)^2
5x^2 = 100
x^2 = 20
x = √20
= 2√5.
So the area of triangle
= 1/2 * base * height
= 1/2 * 2x * x
= x^2
= (2√5)^2
= 20.
The graph is stretch/shrunk by a factor of a. The Domain is h=
