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RoseWind [281]
3 years ago
7

Find the quotient of the complex numbers. Leave answer in polar form.

Mathematics
1 answer:
Goryan [66]3 years ago
4 0
\bf \qquad \textit{division of two complex numbers}
\\\\
\cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies
 \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)]\\\\
-------------------------------

\bf \cfrac{z1}{z2}\implies \cfrac{\frac{1}{8}\left[cos\left(\frac{2\pi }{3}  \right)+i~sin\left(\frac{2\pi }{3}  \right)  \right]}
{\frac{1}{3}\left[cos\left(\frac{\pi }{4}  \right)+i~sin\left(\frac{\pi }{4}  \right)  \right]}
\\\\\\
\cfrac{\quad \frac{1}{8}\quad }{\frac{1}{3}}\left[cos\left(\frac{2\pi }{3}-\frac{\pi }{4}  \right)+i~sin\left(\frac{2\pi }{3}-\frac{\pi }{4}  \right)  \right]
\\\\\\
\cfrac{3}{8}\left[cos\left(\frac{5\pi }{12}  \right)+i~sin\left(\frac{5\pi }{12}  \right)  \right]
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Answer:

The answer is Yes

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Answer:

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Step-by-step explanation:

By algebraic property of functions we have;

(F\cdot \: P)(y) = F(y) \cdot \: P(y)

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See below

Step-by-step explanation:

<u>Given points:</u>

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