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Marat540 [252]
3 years ago
15

Type the correct answer in each box. Round your answers to the nearest hundredth.

Physics
1 answer:
sergey [27]3 years ago
7 0

Hi there!

\large\boxed{PE = 7.35 J, \text{ }v \approx 3.13 m/s}

To find the potential energy of the ball at B, we can use the equation:

PE = mgh

Plug the given gravity, mass, and height:

PE = (1.5)(0.5)(9.8) = 7.35 J

At A, all of this potential energy is changed to kinetic energy, so we can use the following equation:

v = √2KE/m

Plug in the solved for energy and mass:

v = √2(7.35)/1.5

Solve:

v ≈ 3.13 m/s

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Answer:

The answer to the question is

The object would fall 57.625 m in the first 5 seconds

Explanation:

To solve the question, we note that

the height of fall = 490 ft = ‪149.352‬ m

Time to touch the ground = 7 seconds

We are required to find out how far the object falls in the first 5 seconds

We apply the relation

S = u·t + 0.5×g·t ² = We then have

‪149.352‬ = U×7+0.5*9.81*49 From where u = -13 m/s

Therefore to find how far it falls in the first 5 seconds, we have

-13*5 + 0.5*9.81*25 = 57.625 m

5 0
3 years ago
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Assuming a vertical trajectory with no drag, derive the applicable form of the rocket equation for this application
VARVARA [1.3K]

Answer:

The vertical trajectory is governed by Ordinary Differential Equation.

Time derivatives of each state variables.

d(d)/dt = v, d(m)/dt = -d(m-fuel)/dt, d(v)/dt = F/m.

Where V is velocity positive upwards, t is time, m is mass, m-fuel is fuel mass, F is Total force, positive upwards.

Therefore,

F = -mg - D + T, If V is positive and

F = -mg + D - T, If T is negative.

D is drag and the questions gave it as zero.

Explanation:

The two sign cases in derivative equations above are required because F is defined positive up, so the drag D and thrust T can subtract or add to F depending in the sign of V . In contrast, the gravity force contribution mg is always negative. In general, F will be some function of time, and may also depend on the characteristics of the particular rocket. For example, the T component of F will become zero after all the fuel is expended, after which point the rocket will be ballistic, with only the gravity force and the aerodynamic drag force being p

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A student throws a 130 g snowball at 6.5 m/s at the side of the schoolhouse, where it hits and sticks. What is the magnitude of
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Answer:

4.7 N

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130 g = 0.13 kg

The momentum of the snowball when it's thrown at the wall is

p = mv = 0.13*6.5 = 0.845 kgm/s

Which is also the impulse. From here we can calculate the magnitude of the average force F knowing the duration of the collision is 0.18 s

p = F\Delta t

F*0.18 = 0.845

F = 0.845 / 0.18 = 4.7 N

8 0
3 years ago
What is the difference between flashing point, boiling point and melting point​
sp2606 [1]
<h3><u>Answer and explanation;</u></h3>
  • <u>Melting point</u> is defined as the temperature at which solid and liquid phases are in equilibrium. It is the temperature at which a solid changes state from solid to liquid at atmospheric pressure.
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A certain circuit is composed of two series resistors. The total resistance is 10 Ohms. One of the resistors is 4 Ohms. The othe
Mariulka [41]
<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

  • A certain circuit is composed of two series resistors
  • The total resistance is 10 ohms
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<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

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<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

We know that,

In series combination,

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<u>That </u><u>is</u><u>, </u>

Rn in series = R1 + R2 + R3.....So on

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We have,

R1 + R2 = 10 Ω

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