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3 years ago

I REALLY NEED HELP PLEASE (exponents)

Mathematics

2 answers:

gogolik [260]3 years ago

8 0

Answer:

A. or B. im pretty sure a tho try it

Step-by-step explanation:

ratelena [41]3 years ago

7 0

No it is A I can confirm

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What are three equivalent Decimal forms for the number 19

docker41 [41]

Answer:

The numbers; 19.0 , 19.00 and 19.000 are same value as the number 19

Step-by-step explanation:

Here in this question, we simply want to write decimals which would have same value as the number 19 when written.

Let’s start with 19.0

This is absolutely same value as the number 19

Furthermore let’s write 19.00

This is also same value as the number 19

Lastly;

19.000

This is same value as the number 19

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3 years ago

What is the name of the type of data that a scatter plot is used to analyze

DanielleElmas [232]

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4 years ago

ga political candidate has asked you to conduct a poll to determine what percentage of people support her. if the candidate only

Vedmedyk [2.9K]

Answer: 151

Step-by-step explanation:

if prior population proportion is unknown , then the formula is used to find the sample size :

$n=0.25(\frac{z_{\alpha/2}}{E})^2$

, where $z_{\alpha/2}$ = Two tailed critical value for significance level of $\alpha.$

E = Margin of error.

Given : margin of error = 8%= .08

For 95% confidence level , two tailed critical value = 1.96

Now, the required sample size :

$n=0.25(\frac{1.96}{0.08})^2\\\\=0.25(24.5)^2\\\\=150.0625\approx151$

Hence, the size of the sample needed = 151.

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3 years ago

Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,

Ray Of Light [21]

Answer:

The probability that at least 1 defective card is in the sample is $0.9644$

Step-by-step explanation:

Here

N = 140

and n = 20

We will use the below given formula

P(at least 1 defective) = 1 - P( 0 defectives)

P( 0 defectives) =

$= \frac{^{20}C_0 * ^{120}C_{20}}{ ^{140}C_{20}}\\= 0.0356 1-0.0356 \\= 0.9644$

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3 years ago

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4 years ago

Read 2 more answers