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3 years ago

Hi can you please help me with my. Work

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

That even isn’t a real question cause if it wants it to be in order ABC it would start 4 etc

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Polygon PQRS, shown in the figure, is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in p

nata0808 [166]

Based on the above:

The slope of P'Q' is = -3/2

The length of P'Q' is approximately = $\sqrt[3]{13}$

<h3>What is the polygon about?</h3>

The slope of P'Q'

= -6/4 = -3/2

The length of P'Q' =

P'Q' = $\sqrt{6^2 + 4^2}$

= $\sqrt{52}$

= $\sqrt[2]{13}$

Therefore;

P'Q' = $\frac{3}{2}$

P'Q' = $\frac{3}{2}$ x $\sqrt[2]{13}$

= $\sqrt[3]{13}$

Learn more about polygon from

brainly.com/question/1592456

#SPJ1

7 0

1 year ago

(-7.5) - 3.3 simplify the expression

dlinn [17]

The answer to your question is <span>−10.8</span>

8 0

3 years ago

Read 2 more answers

2root 3 x 3 root 8 fully simplified

LuckyWell [14K]

Answer:

$12\sqrt{6}$

Step-by-step explanation:

<h3>Given expression</h3>

$2 \sqrt{3} *3\sqrt{8}$

<h3>Simplify the expression in steps as below</h3>

$2 \sqrt{3} *3\sqrt{8} =$
$2 \sqrt{3} *3\sqrt{2^2*2} =$
$2 \sqrt{3} *3*2\sqrt{2} =$
$2*6* \sqrt{3} *\sqrt{2} =$
$12* \sqrt{3*2} =$
$12\sqrt{6}$

Used properties in solution process:

$\sqrt{a^2} =a$
$\sqrt{a}\sqrt{b} =\sqrt{ab}$

8 0

2 years ago

For any linear function f(x) = mx + b, when does 5f(x) = f(5x)?

S_A_V [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

Choose one <br> Help me please

AfilCa [17]

Answer:

Step-by-step explanation:

Smallest to Largest

Natural numbers

Whole numbers

Integers

Rational numbers

4 0

2 years ago