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Kobotan [32]
3 years ago
14

What is x? help plz.

Geography
1 answer:
Elodia [21]3 years ago
6 0

Answer:

You need tto find the value of x........

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In what way does the federal legislative process of passing a bill into law use the system of checks and balances? A. Congress c
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A. Congress can overide the presidents veto of the bill if they have 2/3 majority vote
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Plzz help....What is Soil Erosion..... 20 pts​
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Erosion or degradation of soils. It is the loss of it, mainly due to factors such as water and air currents, particularly in dry lands without vegetation, in addition to ice and other factors. Soil erosion reduces its fertility because it causes the loss of minerals and organic matter.

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Imagine you are taking a trip across the globe. Describe the terrestrial biomes you would encounter along the way, staring from
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Answer:

the  terrestrial biomes we would encounter along the way , staring from the North pole all the way down to the south pole are ;

  • polar ice
  • tundra
  • Boreal forest
  • temperate forest
  • temperate grassland
  • desert
  • mountain
  • savannah
  • tropical forest
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check below for explanation

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Which are characteristics of a desert ecosystem?
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Calculate the amount, in grams, of an original 300-gram sample of radioactive isotope Potassium-40 remaining after
Aleksandr [31]

Answer:

The current amount of the Potassium-40 sample is approximately 37.521 grams.

Explanation:

The amount of the sample of the radioactive isotope decays exponentially in time, the amount of mass of the sample as a function of time (m (t)), in grams, is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

m_{o} - Initial mass, in grams.

t - Time, in years.

\tau - Time constant, in years.

The time constant can be found from half life (t_{1/2}), in years, described in statement:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 300\,g, t = 3.9\times 10^{9}\,yr and t_{1/2} = 1.3\times 10^{9}\,yr, then the current amount of the sample is:

\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}

\tau \approx 1.876\times 10^{9}\,yr

m = (300\,g)\cdot e^{-\frac{3.9\times 10^{9}\,yr}{1.876\times 10^{9}\,yr} }

m\approx  37.521\,g

The current amount of the Potassium-40 sample is approximately 37.521 grams.

4 0
3 years ago
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