How can you determine if two triangle angles are similar using their angle measurements???? In ur own words !!

Mathematics

1 answer:

Andrej [43]1 year ago

4 0

Answer:

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Step-by-step explanation:

hope this helps:0

You might be interested in

The mean heigh of American Males is 69.5 inches. The height of the 43 male presidents have a mean 70.78 inches and a standard de

Arisa [49]

Answer:

There is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

Step-by-step explanation:

The given parameters are;

The mean height of American Males, μ = 69.5 inches

The mean height of 43 male presidents, $\overline x$ = 70.78

The standard deviation, s = 2.77 inches

The number of male presidents = 43

The null hypothesis; H₀ μ = $\overline x$

The alternative hypothesis; Hₐ μ ≠ $\overline x$

The significance level, α = 0.05

The t test for the sample with unknown population standard deviation is given as follows;

$t=\dfrac{\bar{x}-\mu }{\dfrac{s }{\sqrt{n}}}$

Therefore, we have;

$t=\dfrac{70.78-69.5 }{\dfrac{2.77 }{\sqrt{43}}} \approx 3.0302$

The degrees of freedom, df = n - 1 = 43 - 1 = 42

The critical 't' value = 2.0181

Therefore, given that the t test value is larger than the critical-t, we reject the null hypothesis, therefore, there is sufficient statistical evidence to suggest that the US presidents are taller than the average American male

4 0

2 years ago

Will give Brainliest! What is the simplified form of the seventh root of x to the fifth power times the seventh root of x to the

jekas [21]

Answer:

2) x times the seventh root of x cubed

Step-by-step explanation:

$\displaystyle\sqrt[7]{x^5}\cdot\sqrt[7]{x^5}=\sqrt[7]{x^{5+5}}\\\\=\sqrt[7]{x^{7+3}}=\sqrt[7]{x^7}\cdot\sqrt[7]{x^3}\\\\=x\sqrt[7]{x^3}$