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2 years ago

Pls helppp 3 part question

Mathematics

2 answers:

Naddik [55]2 years ago

6 0

I cant see the blueprint, but i will help you

defon2 years ago

3 0

What Does The Scale Look Like?

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Pleaseeeeeeeee helppppppppp meeeeeeeeeee

Kay [80]

Answer:

Step-by-step explanation:

it is the thing ok

6 0

2 years ago

A researcher is interested in the lengths of brook trout, which are known to be approximately Normally distributed with mean 80

aliya0001 [1]

Answer:

$P(X$

And we can find this probability with the normal standard distirbution or excel and we got:

$P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the lenghts of a population, and for this case we know the distribution for X is given by:

$X \sim N(80,5)$

Where $\mu=80$ and $\sigma=5$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability with the normal standard distirbution or excel and we got:

$P(z$

6 0

3 years ago

PLSS HURRY FOR 50 POINTS

serg [7]

A !!!!!!!!!!!!!!!!!!!

7 0

2 years ago

Read 2 more answers

A rubber ball is dropped from the top of a hole. Exactly 20 seconds later, the sound of the rubber ball hitting bottom is heard.

gayaneshka [121]

9514 1404 393

Answer:

4192.9 ft

Step-by-step explanation:

We assume your falling-distance formula is supposed to be ...

s = 16t²

So, the time required to fall distance s is ...

t = √(s/16) = (1/4)√s

The time required for sound to travel distance s is ...

s = 1100t

t = s/1100

Then the sum of the time for the ball to fall and the time for the sound to travel back is ...

(1/4)√s + s/1100 = 20

275√s = 22000 -s . . . . . multiply by 1100 and subtract s

75625s = s^2 -44000s +484,000,000 . . . square both sides

s^2 -119,625s +484,000,000 = 0 . . . . put in standard form

s ≈ (1/2)(119,625 ±√12,374,140,625) = {4192.943, 115432.057}

Only the smaller of these two solutions makes any sense in this problem.

The hole is about 4192.9 feet deep.

_____

Additional comment

The distance equation for the falling object presumes a vacuum. The sound transmission presumes the presence of air, so the question setup is self-contradictory.

7 0

3 years ago

Evaluate the value of x to 1 d.p Thank you

Keith_Richards [23]

Answer:

value of x = 2.8

Step-by-step explanation:

By law of cosines,

${a}^{2} = {b}^{2} + {c}^{2} - 2 \times b \times c \times cos(100) \\ {x}^{2} = {13}^{2} + {10}^{2} - (2 \times 13 \times 10 \times cos100) \\ = 169 + 100 - 260 \times 0.862 \\ = 269 - 260 \times 0.862 \\ = 7.758 \\x = \sqrt{7.758 } \\ = 2.785 \\ = approx \: 2.8$

6 0

2 years ago