Answer:
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.
The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23
Your answer is D. the last one :)
Divide the 5 with 42.00 and see the answer u got
Answer: 26∗34 2 6 ∗ 3 4
Step-by-step explanation:
Answer:
(-2,1)
Step-by-step explanation:
I know