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Vlad1618 [11]
3 years ago
8

Evaluate the expression for x=2 and y=4. (x5y?)/(x3y5)

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

(2 x 5 x 5) / (2 x 3 x 4 x 5)

=40/120

= 4/12

= 1/3

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A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
son4ous [18]

Answer:

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.325

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.325*\frac{20.28}{\sqrt{20}} = 12.17

The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.

The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

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3 years ago
Simplify 6 - (-2) - 3(-5).<br> -11<br> -7<br> 19<br> 23
Sergeeva-Olga [200]
6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23

Your answer is D. the last one :)
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Divide the 5 with 42.00 and see the answer u got
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