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3 years ago

Please help me, i will mark brainliest

Mathematics

1 answer:

Pani-rosa [81]3 years ago

8 0

Answer:

B-Tickets

B-15x-500≥1000

C-x≥100

Step-by-step explanation:

X is the variable because you need to find how many tickets need to be sold

The answer is B because they need to raise $1000 or more

15x-500≥1000 (add 500 to both sides)

15x≥1500

x≥100

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A hacker is trying to guess someone's password. The hacker knows (somehow) that the password is 10 characters long, and that eac

Gnoma [55]

The probability that the hacker guesses the password on his first try is:

P = 1/(62^10) = 1.19*10^(-18)

We know that the password is 10 characters long.

In each one of these, we can put.

One lower case letter (26 of these)

One upper case letter (26 of these)

one numerical digit (10 of these)

So, for every single digit, we have a total of:

26 + 26 + 10 = 62 options

Now we can find the total number of different passwords, which will be equal to the product between the number of options for each one of the characters.

We know that for each character we have 62 different options.

And we have 10 characters.

Then the product between the numbers of options is:

C = 62^10

Then if the hacker does a random guess, the probability that the random guess is correct is one over the total number of possible combinations.

P = 1/C = 1/(62^10)

The probability that the hacker guesses the password on his first try is:

P = 1/(62^10) = 1.19*10^(-18)

If you want to read more about probability, you can read:

brainly.com/question/427252

4 0

3 years ago

In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence

Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

6 0

3 years ago

Solve for x 4 - ( 2x - 2) + 3x = 4(x + 5) - 3(x-2)-10

erica [24]

Step-by-step explanation:

4 + x + 3x = 4 ( 5x ) - 3 ( x ) - 10

4 + x + 3x = 4 + 5x - 3 + x - 10

x + 3x + 5x + x = 4 + 4 - 3 - 10

10x = 21

10x % 10 = 21 % 10

x = 2,1

8 0

3 years ago

Determine whether the situation calls for a survey, an observational study, or an experiment.

Elis [28]

Answer:

b. observational study

Explanation:

Observational studies are commonly used in order to know the effects of a treatment or drug. This study recruits people (the population of interest) to participate and these people are then interviewed and observed on a face-to-face visit. This allows clinical investigation regarding the safety of the new medication, including its side effects and adverse effects. So, this allows the researcher to know the symptoms of the new drug including whether it can reduce migraine to people.

The study also allows the employment of different designs, thereby paving way to a better patient care.

4 0

3 years ago

A campaign strategist wants to determine whether demographic shifts have caused a drop in allegiance to the Uniformian Party in

Bas_tet [7]

Answer:

d. There is not enough evidence to support the hypothesis that the proportion of Uniformian voters has decreased.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that there is a significant drop in allegiance to the Uniformian Party in Bowie County.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.62\\\\H_a:\pi$

The significance level is 0.05.

The sample has a size n=196.

The sample proportion is p=0.57.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.62*0.38}{196}}\\\\\\ \sigma_p=\sqrt{0.001202}=0.035$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.57-0.62+0.5/196}{0.035}=\dfrac{-0.047}{0.035}=-1.369$

This test is a left-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z$

As the P-value (0.0855) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is a significant drop in allegiance to the Uniformian Party in Bowie County.

6 0

3 years ago