Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

$A_s=2 * A_t$

Where At is the area of each triangle.

$\displaystyle A_t=\frac{AB*BC/2}{2}$

$\displaystyle A_t=\frac{AB*BC}{4}$

We know AB=3 and BC=2, thus:

$\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}$

Simplifying:

$\displaystyle A_t=\frac{3}{2}$

Finally:

$\displaystyle A_s=2 * \frac{3}{2}$

$A_s=3$

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0

2 years ago

In the middle school debate club, 30% of the members are in sixth grade. If there are 12 graders in the club, how many total mem

Slav-nsk [51]

The answer is D because you just multiply the percent times 40 to get 12.

6 0

2 years ago

Read 2 more answers

PLEASE HELP!!! <br>What is mDBC?

defon

Answer:

i dont get the question sorry

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers