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2 years ago

4+35x+52X Find x and the value

Mathematics

2 answers:

Ostrovityanka [42]2 years ago

8 0

4+35x+52x
^
35x + 52x = 87x

finally answer: 4+87x

iren2701 [21]2 years ago

4 0

Answer: 4+87x

Step-by-step explanation:

4+35+52

Combine like terms

4+35x+52x

4+87x

rearrange terms

=4+87x

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Icy River increased the price of a $1.15 cola by 15%. Find the increase in price and the new price. round to the nearest cent

madam [21]

15% x
100 1.15 X is your variable, your unknown number and 15% has to always be over 100 , Then you have to cross multiply and divide 100 because that is the only number basically you have to just multiply across and divide 100 to make it to the nearest cent you have to round the last two numbers after the decimal Representing money.. Hope this helps!!

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3 years ago

Camden is going to invest $600 and leave it in an account for 12 years. Assuming the

UkoKoshka [18]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}$

$920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r$

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2 years ago

342,802 to the nearest hundred thousands

Maksim231197 [3]

1. The number 3 is located in the hundred thousands place.

2. Since the number 4 is located in the ten thousands place, it's telling 3 to stay the same

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8, etc...

342,802 ⇒ 300,000

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3 years ago

Read 2 more answers

Subtract 2x 2 - 6x - 4<br> from 4x 2 - 4x + 3.

mafiozo [28]

X subtracted from y means y-x
(4x^2-4x+3)-(2x^2-6x-4)
4x^2-4x+3-2x^2+6x+4
4x^2-2x^2-4x+6x+3+4=
2x^2+2x+7

6 0

2 years ago

What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4

Alecsey [184]

Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: $f(x)=\dfrac{3x^2}{x^2-4}$

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. $x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2$

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at $y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}$

i.e. $y=\dfrac{3}{1}=3$

Hence, f(x) will have horizontal asymptote at y=3.

3 0

3 years ago