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Wewaii [24]
2 years ago
8

Rewrite the fraction pairs with common denominators

Mathematics
1 answer:
Nataliya [291]2 years ago
3 0

Answer:

a) \frac{3}{20} and \frac{16}{20} = \frac{19}{20}

b) \frac{8}{21} and \frac{18}{21} = 1\frac{5}{21}

c) \frac{18}{72} and \frac{32}{72} = \frac{25}{36}

Step-by-step explanation:

a) \frac{3}{20} and \frac{4}{5}

\frac{4}{5} x 4 = \frac{16}{20}

\frac{3}{20} and \frac{16}{20} = \frac{19}{20}

b) \frac{8}{21} and \frac{6}{7}

\frac{6}{7} x 3 = \frac{18}{21}

\frac{8}{21} and \frac{18}{21} = 1\frac{5}{21}

c) \frac{2}{8} and \frac{4}{9}

\frac{2}{8} x 9 = \frac{18}{72}

\frac{4}{9} x 8 = \frac{32}{72}

\frac{18}{72} and \frac{32}{72} = \frac{25}{36}

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The key to solving this question is first knowing how many cubic cm are in one cubic m:

The ratio is always 1000000 cubic cm in 1 cubic meter.

Knowing this, we calculate how many cubic cm are in 5 cubic meters!

<u>1000000 cubic cm </u>= <u>1 </u><span><u>cubic m</u>
      x </span>cubic cm           5 cubic m

x = 1000000 cubic cm x 5 cubic m ÷ 1 cubic m
x = 5<span>000000 cubic cm

Hope this helps!
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4 0
2 years ago
Read 2 more answers
LONG WORD PROBLEM I KNOW! PLEASE ILL GIVE THANKS BRAINLIEST AND POINTS FOR THIS ANSWER! PLEASE!
11Alexandr11 [23.1K]
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
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then X < -20
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5 0
3 years ago
Sarah needs to have a plumber come to her house and fix a leaky faucet in her bathroom. The plumber charges $50 to come to her h
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Answer:

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Step-by-step explanation:

Hi

As Sarah has only $234.50 in her savings and the plumber charges $50 just to come to her home, so left-over $184.50 of her saving for pay work hours.

Then as the plumber charges $30.75 per hour we have that \frac{\$ 184.50}{\$ 30.75/h}=6h is the maximum amount of hours that Sarah can have the plumber work on her faucet.

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Answer:

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5 0
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